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6.16.3  Defining algebraic functions

Defining a function from ℝp to ℝq

If expr is an expression possibly involving a variable x, you can use it to define a function f either by
f(x):=expr
or f := x->expr
(see Section 5.5.1).


Warning!!!
The expression after -> is not evaluated. You should use unapply (see Section 6.15.2) if you expect the second member to be evaluated before the function is defined.


Example.
To define f:(x)→ x*sin(x),
Input:

f(x):=x*sin(x)

or:

f:=x->x*sin(x)

then:

f(pi/4)

Output:

π
2
8

You can similarly define a function of several variables, by replacing x by a sequence (x1,…,xp) or a list [x1,…,xp] of variables.


Example.
Input:

f(x,y):=x*sin(y)

or:

f:=(x,y)->x*sin(y)

then:

f(2,pi/6)

Output:

1


You can also define a function with values in ℝq by replacing expr by a sequence (expr1,…,exprq) or list [expr1,…,exprq] of expressions.


Examples.

Defining families of function from ℝp−1 to ℝq using a function from ℝp to ℝq

Suppose that the function f: (x,y) → f(x,y) is defined, and you want to define a family of functions g(t) such that g(t)(y):=f(t,y) (i.e. t is viewed as a parameter). Since the expression after -> (or :=) is not evaluated, you should not define g(t) by g(t):=y->f(t,y); you have to use the unapply command (see Section 6.15.2).

For example, to define f:(x,y)→ xsin(y) and g(t):yf(t,y):
Input:

f(x,y):=x*sin(y);g(t):=unapply(f(t,y),y)

then:

g(2)

Output:

y↦ 2 siny

Input:

g(2)(1)

Output:

2 sin
1

For another example, suppose that you want to define the function h: (x,y) → [x*cos(y),x*sin(y)] and then you want to define the family of functions k(t) having t as parameter such that k(t)(y):=h(t,y). To define the function h(x,y)
Input:

h(x,y):=(x*cos(y),x*sin(y))

To define properly the function k(t): Input:

k(t):=unapply(h(x,t),x)

then:

k(2)

Output:

x↦ 
x cos
2
,x sin
2

(x)->(x*cos(2),x*sin(2))

Input:

k(2)(1)

Output:

cos
2
,sin
2

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